[2x-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)],其中x=-1/2,y=-1

来源:百度知道 编辑:UC知道 时间:2024/05/13 17:44:45
[2x-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)],其中x=-1/2,y=-1
过程详细点

[2x-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]
=(-1+3/2*1/2)(5/2*3/2-1*3)
=-1/4*3/4
=-3/16 或

[2x-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]
=(2x-x~+y~)(4-x~-4+y~)
=(2x-x~+y~)(y~-x~)
把x=-1/2,y=-1代入
=(-1-1/4+1)(1-1/4)
=-3/16

~为平方

[2x-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]
=[2x-x^+y^][4-x^-4+y^]
=[2x-x^+y^][-x^+y^]
=-2x~+x!-y^x^+2xy^-x^y^+y!
=-2x~+x!-2y^x^+2xy^+y!
把x=-1/2,y=-1带入上式:
=1/4+1/16+1+1+1
=53/16
(其中^为平方 ~为3次方 !为4次方)

解:原式={2X-X*X+Y*Y}{4-X*X+{(-Y)*(-Y)-4}
={2X-X*X+Y*Y}{Y*Y-X*X}
然后带入就行了

ikfphgonkpcl,bm'hndplkldkp